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一題有關POISSON分配之統計題!!

A store selling newspapers orders only n = 4 of a certain newspaper because the manager does not get many calls for that publication. If the number of requests per day follows a Poisson distribution with mean 3.(a) What is the expected value of the number sold?(b) How many should the manager order so that the chance of running out is less than 0.05?
(a) Let X be Poisson distributed with mean 3. Since n=4

the store can only sell 0

1

2

3

or 4 newspapers. If X=5 only four newspapers are sold. If we let Y be the number of newspapers sold

then P(Y=0)=P(X=0)

P(Y=1)=P(X=1)

P(Y=2)=P(X=2)

P(Y=3)=P(X=3)

P(Y=4)=P(X

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